1. Wiggle Sort
- O(nlogn): Sort first + starting from the second elements, swap two continuous elements
- O(n) : swap elements based on even or odd index
- 先sort,然后从第二个元素开始,swap(2nd, 3rd), swap(4th, 5th)....这样子就可以得到一个wiggle sorted array
class Solution {
public void wiggleSort(int[] nums) {
if (nums == null || nums.length <= 1) return;
Arrays.sort(nums);
for (int i = 1; i < nums.length; i+=2) {
if (i + 1 < nums.length) swap(nums, i, i + 1);
}
}
private void swap(int[] nums, int a, int b) {
int temp = nums[a];
nums[a] = nums[b];
nums[b] = temp;
}
}
可以总结出一个规律
当i为奇数时,nums[i] >= nums[i - 1] --> 要大于或者等于前一位
当i为偶数时,nums[i] <= nums[i - 1] --> 要小于或者等于前一位
如果不符合,则与前一位数字交换
//todo wiggle sort ii